49x^2+6=87

Solution for 49x^2+6=87 equation:

49x^2+6=87

We move all terms to the left:

49x^2+6-(87)=0

We add all the numbers together, and all the variables

49x^2-81=0

a = 49; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·49·(-81)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*49}=\frac{-126}{98}
=-1+2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*49}=\frac{126}{98}
=1+2/7
$